Objective
At the end of this lesson, students should be able to multiply and divide directed numbers.
The rules for multiplying and dividing two directed number are as follows;
Example 1
Solution
Example
Simplify:
a) (–2)(–3)(–4) b) (–1)(–2)(–1)(–3)(–4)(–2)(–1)
Solution
Exponents
Example 1
Simplify: a) (–3)2 b) –32
Solution
In the example b) the square “to the power 2” was only on the 3; it was not on the minus sign. Parentheses or brackets makes all the difference in the two examples.
Example 2
Simplify
1) a) (–5)3 b) (–2)4
1) a) (–5)3 = (–5)(–5)(–5)
= (25)(–5)
= –125
b) (–2)4 = (–2)(–2)(–2)(–2)
= + 4 x + 4
= (4)(4)
= 16
Example 3
a = –2 and b = –6
Work out the following
a) a2 b)a2 + b2 c) b3 – a2 d) (a – b)2
Solution
a) a2
= –2 × –2
= 4
b) a2 + b2
= (–2 × – 2)+( –6 × –6)
= 4 + 36 = 40
c) b2 – a2
= (–6 × –6) – (–2 × –2)
= 36 – 4
= 32
d) (a – b)2
= (–2 – –6)2
= (–2 + 6)
= (4)2
= 16
BODMAS
Example 1
Simplify the following.
Solution
In this problem you can see all the different operations. When there is more than one operation involved in a problem, we have to follow the order of operations.
(a) 23 – (5– –7)
(First, carry out the operations inside the brackets, – – = +)
= 23 – (5 + 7)
= 23 – (12) (next, remove the brackets )
= 11
(b) 5 × – 4 + –8 (Remember the order, × before +)
= –20 + –8 (+ – = –)
= – 20 – 8
= –28
(c) –25 ÷ [ 5 × –2 – (–3 ×5) ]
(In this problem, ( )brackets are inside the [ ] brackets, so first you have to solve the inner brackets before and the outer brackets.)
= – 25 ÷ [5 × –2 – (–15)] (–3 ×5 = –15 )
= – 25 ÷ [–10 – (–15) ] (5 × –2 = –10)
= –25 ÷ [–10 + 15] (– – = + )
= –25 ÷ [5] (– ÷ + = – )
= – 5
d) –8 + (6 × –3 – 2 ) ÷ –4 – –8 ( 6 x –3 –2 = –18 –2)
= –8 +(–18 –2 )÷ –4 + 8 –18 –2 =–20
= –8 + –20 ÷ 4 –20 ÷ 4=–5
= –8 – 5
= –13